代码编织梦想

2022年蓝桥杯真题-积木画【最简单的矩阵快速幂】-爱代码爱编程

问题描述 小明最近迷上了积木画, 有这么两种类型的积木, 分别为 I 型(大小为 2 个单位面积) 和 L 型 (大小为 3 个单位面积): 同时, 小明有一块面积大小为 2×N 的画布, 画布由 2×N 个1×1 区域

POJ 1995 Raising Modulo Numbers【快速幂】-爱代码爱编程

Description People are different. Some secretly read magazines full of interesting girls’ pictures, others create an A-bomb in their cellar, others like using Windows, and some l

POJ 3070 Fibonacci【矩阵快速幂】-爱代码爱编程

Description In the Fibonacci integer sequence, F 0 =

LeetCode C++ 面试题 08.05. Recursive Mulitply LCCI【Recursion/Math】中等-爱代码爱编程

Write a recursive function to multiply two positive integers without using the * operator. You can use addition, subtraction, and bit shifting, but you should minimize the number

LeetCode C++ 50. Pow(x, n)【Recursion】中等-爱代码爱编程

Implement pow(x, n), which calculates x raised to the power n (i.e. xn). Example 1: Input: x = 2.00000, n = 10 Output: 1024.00000 Example 2: Input: x = 2.10000, n = 3 Outp

算法学习笔记(5) 快速幂和矩阵快速幂-爱代码爱编程

文章目录 1. 快速幂概念(1) 快速幂递归实现(2) 快速幂迭代实现2. 快速幂取模3. 快速幂拓展4. 矩阵快速幂5. 应用题目 1. 快速幂概念 快速幂 Exponentiation By Squaring(平方求幂)是一种简单有效的算法,可以以 O

CF - 450 -- B.Jzzhu and Sequences【矩阵快速幂+如何构造核心矩阵】-爱代码爱编程

Jzzhu and Sequences 思路 题意让我们求f[i] = f[i-1] + f[i+1] 将其转化为 f[i] = f[i - 1] + f[i - 2](i >= 2) 如果你不会构造核心矩阵,那么这篇文章将会帮助你如何构造核心矩阵 AC代码 #include<iostream> #include<cs

HDU - 2604 -- Queuing【矩阵快速幂+DP】-爱代码爱编程

Queuing Description Queues and Priority Queues are data structures which are known to most computer scientists. The Queue occurs often in our daily life. There are many people l

HDU - 1588 -- Gauss Fibonacci【矩阵快速幂升级版,如何构造核心矩阵】-爱代码爱编程

Gauss Fibonacci Description Without expecting, Angel replied quickly.She says: "I’v heard that you’r a very clever boy. So if you wanna me be your GF, you should solve the probl

POJ - 3233 -- Matrix Power Series:【矩阵快速幂基础版,如何构造核心矩阵】-爱代码爱编程

Matrix Power Series Description Given a n × n matrix A and a positive integer k, find the sum S = A + A2 + A3 + … + Ak. Input The input contains exactly one test case. The fir

POJ - 3070 -- Fibonacci:【矩阵快速幂基础版】-爱代码爱编程

Fibonacci Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequence are: 0,

HDU - 4704 -- Sum【快速幂+费马小定理】-爱代码爱编程

Sum Description Sample Input 2 Sample Output 2 Hint For N = 2, S(1) = S(2) = 1. The input file consists of multiple test cases. 题意: 首先题意是让我们求一个n被划分为k短,能有几种可能。 举个列子,比如说

POJ -1995 -- Raising Modulo Numbers【快速幂基础版】-爱代码爱编程

Raising Modulo Numbers Description People are different. Some secretly read magazines full of interesting girls’ pictures, others create an A-bomb in their cellar, others like u

HDU - 1420 -- Prepared for New Acmer【快速幂基础版】-爱代码爱编程

Prepared for New Acmer Description 集训进行了将近2个礼拜,这段时间以恢复性训练为主,我一直在密切关注大家的训练情况,目前为止,对大家的表现相当满意,首先是绝大部分队员的训练积极性很高,其次,都很遵守集训纪律,最后,老队员也起到了很好的带头作用,这里特别感谢为这次DP专题练习赛提供题目和测试数据的集训队队长xhd同学.

快速幂与矩阵快速幂【入门+基础】-爱代码爱编程

这里写目录标题 快速幂1.解决溢出问题:2.降低复杂度:递归实现非递归实现练习题矩阵快速幂代码如何构造核心矩阵优化同余定理费马小定理练习题 快速幂 如果我们要计算𝑎𝑏 mod p,我们首先能想到的便是for循环: int ans=1; for(int i=1;i<=b;i++) ans*=a; return ans%p;