代码编织梦想

atcoder beginner contest 342 (abcdefg题)视频讲解-爱代码爱编程

A - Yay! Problem Statement You are given a string S

codeforces round 913 (div. 3) a~e_a. removal of unattractive pairs-爱代码爱编程

目录 A. Rook  问题分析:  B. YetnotherrokenKeoard 问题分析:   C. Removal of Unattractive Pairs 问题分析:   D. Jumping Through Segments 问题分析:   E. Good Triples 问题分析:   A. Rook 

daiwa securities co. ltd. programming contest 2023(atcoder beginner contest 331)-爱代码爱编程

Daiwa Securities Co. Ltd. Programming Contest 2023(AtCoder Beginner Contest 331) - AtCoder #include<bits/stdc++.h> using namespace std; #define int long long signed main

abc332 a-爱代码爱编程

AtCoder Beginner Contest 332 - AtCoder 打的最难受的一集,前三题阅读理解,D暴力没想出来,E典的子集dp,F一眼区间乘加的线段树但是没时间写,掉大分,要被新生单调队列优化了 A - Online Shopping 题意: 购物,N种商品,每种商品Pi元买Qi个,满S元包邮,否则加K元邮费,问实付多少 题解:

atcoder beginner contest 332 a-爱代码爱编程

比赛链接:https://atcoder.jp/contests/abc332比赛时间:2023年 12 月 10 日 20:00-21:40 A题:Online Shopping 标签:枚举、模拟题意:给定

atcoder beginner contest 333 a~f-爱代码爱编程

A.Three Threes(循环) 题意: 给出一个正整数 N N

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Daiwa Securities Co. Ltd. Programming Contest 2023(AtCoder Beginner Contest 331) - AtCoder 掉大分的一场。D好若至调了好久,EF倒是全都一眼出做法...然而F手搓写bug了直到赛后才找到sb错误... A - Tomorrow 题意: 每年M月,每个月D天,求

atcoder beginner contest 332 (a -爱代码爱编程

目录 [A - Online Shopping](https://atcoder.jp/contests/abc332/tasks/abc332_a)Problem StatementConstraintsIn

atcoder beginner contest 333 (a -爱代码爱编程

目录 [A - Three Threes](https://atcoder.jp/contests/abc333/tasks/abc333_a)Problem StatementConstraintsInput

atcoder beginner contest 337 a-爱代码爱编程

A - Scoreboard #include <iostream> #include <cstring> #include <algorithm> using namespace s

atcoder beginner contest 337 (abcdeg题)-爱代码爱编程

A - Scoreboard Problem Statement Team Takahashi and Team Aoki played N

atcoder beginner contest 337 a~g_atcoder abc337-爱代码爱编程

A.Scoreboard(循环) 题意: 两个队伍进行 N N

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Toyota Programming Contest 2024#1(AtCoder Beginner Contest 337) - AtCoder 手速五题之后看FG,一看榜G过的比F多...两题都有思路然后先开写了F像是大模拟写了一堆bug,赛后对拍调bug调完疯狂re,发现是对数组双倍操作了但数组长度没开两倍... G赛时就看了眼猜了个动态开点权值

atcoder beginner contest 340(a-爱代码爱编程

A - Arithmetic Progression (atcoder.jp)         1.思路:循环输出即可         2.代码: #include <bits/stdc++.h> #define rep(i,z,n) for(int i = z;i <= n; i++) #define per(i,n,z) for

atcoder beginner contest 340c -爱代码爱编程

problem link Naively, a brute force recursion solution be implemented with

kajima corporation contest 2024(atcoder beginner contest 340)(a~d)-爱代码爱编程

A - Arithmetic Progression 给你A,B,D,输出A,A+D,A+2*D,...到B为止,一个循环就可以解决。 #include <bits/stdc++.h> //#define int long long #define per(i,j,k) for(int (i)=(j);(i)<=(k);++(i)

kajima corporation contest 2024(atcoder beginner contest 340)abcdef 视频讲解-爱代码爱编程

这场比较郁闷,C题短路,连续4次WA,导致罚时太多 A - Arithmetic Progression Problem Statement Print an arithmetic sequen

atcoder beginner contest 327 f -爱代码爱编程

F - Apples 题意 有 N N

atcoder begginer contest 327 讲解(abc327 a~f题)_atcoder beginner contest 327-爱代码爱编程

A - ab Description Problem Statement You are given a string S

abc208(a-爱代码爱编程

A #include<bits/stdc++.h> using namespace std; int main() { int a,m; cin>>a>>m; if(m<=a*6&&m>=a)cout<<"Yes"<<endl; else cout&l