rule110电路-爱代码爱编程
有一个一维单元格数组(开或关)。在每个时间步长中,每个单元格的状态都会发生变化。在规则 110 中,每个单元格的下一个状态仅取决于其自身及其两个相邻单元,如下表所示:
思路:将表格用卡诺图化简求出电路表达式
将左记为l,右记为r,中心记为c,最后化简出来的表达式是:res = c&~(l&r) + (~l&r) + (l&r&~c);
module top_module(
input clk,
input load,
input [511:0] data,
output [511:0] q
);
always @ (posedge clk) begin
if (load)
q <= data;
else begin
for (integer i = 0; i < 512; i++) begin
if (i==0)
q[0] <= (q[i]&~(q[i+1]&0))|(~q[i+1]&0)|(q[i+1]&0&~q[i]);
else if (i==511)
q[511] <= (q[i]&~(0&q[i-1]))|(1&q[i-1])|(0&q[i-1]&~q[i]);
else
q[i] <= (q[i]&~(q[i+1]&q[i-1]))|(~q[i+1]&q[i-1])|(q[i+1]&q[i-1]&~q[i]);
end
end
end
endmodule
分类讨论一下边界问题即可得出答案。